Question

A 120-V AC circuit has a 20.0-Ω resistor connected in series to a capacitor for which...

A 120-V AC circuit has a 20.0-Ω resistor connected in series to a capacitor for which the capacitive reactance is XC = 31.0 Ω .

What is the average rate at which energy is dissipated in the circuit?

If the resistance in the circuit is 25.0 Ω, what would the capacitive reactance have to be in order for the power factor to be 0.27?

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Answer #1

Vo : 120v R= 20 n Xc = vz Vosin wt at whiih Mate averaye, (Pau) Avenaye pawen disipate d in Ciruuit is euergy the Vo x I. PauSquaring both Sides R²= (Pf Ý CRZ+ xc²) R² + xc² (PF)Z Rと= (PF)? (PA) (o-27)* Xcz 89.15 e

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