The problem is based on the concept of epoxide ring opening in the presence of a base. In basic medium, epoxide undergo ring opening via mechanism.
Epoxides are three-membered ring structures which contain an oxygen atom at one vertex and two carbon atoms at other two vertices. The carbon atoms in epoxides ring are electrophilic and therefore, react with nucleophile which opens the strained ring.
An example of ring-opening of symmetrical epoxide is as follows:
In case of unsymmetrical epoxide ring, the nucleophile attacks from the less hindered side. An example of ring-opening of unsymmetrical epoxide is as follows:
The mechanism of the ring opening reaction is as follows:
The reaction mechanism is as follows:
Ans:The intermediate formed in the reaction is,
The final product of the reaction is,
Draw the intermediate and final organic structures in the following two-step reaction, showing the correct stereochemistry.
??? Draw the intermediate and final organic structures in the following two-step reaction, showing the correct stereochemistry.
Draw the intermediate and final organic structures in the following two-step reaction, showing the correct stereochemistry.
Draw the structures of the intermediate compound and final organic product in the following two-step reaction. The molecular formula of the final product is given.
Draw the correct organic product for the following reaction. Show stereochemistry clearly. Draw the correct organic product for the following reaction. Show stereochemistry clearly.
Draw the structures of the organic products in each reaction of the following two-step synthesis.
draw the final organic product of the following three-step reaction of bromomethylbenzene Draw the final organic product of the following three-step reaction of bromomethylbenzene.
Draw the structures of the organic products in each reaction of the following two-step synthesis. (Hint: The nucleophilic amine attacks the electrophilic carbonyl carbon, and the resulting intermediate undergoes a proton shift and dehydration. Recall what is eliminated in a dehydration process. The second step is a reduction reaction; the reducing agent is NaBH3CN (or H2, metal catalyst). The aromatic ring is unaffected by these reagents. Look at the product of the first reaction and consider what can be easily...
What are the products formed in this two-step reaction? What is the stereochemistry of the final product? Draw your answers as line structures and show stereochemistry of asymmetric centers with wedges and dashes. NaH(1eq) (reacts once) Bry OH Hexane Et20
Draw the structures of the organic products in each reaction of the following two-step synthesis. (Hint: The nucleophilic amine attacks the electrophilic carbonyl carbon, and the resulting intermediate undergoes a proton shift and dehydration. Recall what is eliminated in a dehydration process. The second step is a reduction reaction; the reducing agent is NaBH3CN (or H2, metal catalyst). The aromatic ring is unaffected by these reagents. Look at the product of the first reaction and consider what can be easily...
Draw the structures of the expected organic product(s) formed in the following reactions including correct stereochemistry. If more than one product is possible draw all products and write major or minor product where necessary. Indicate what the mechanism of the reaction is. Assume all reagents listed are present in excess unless otherwise noted. If no reaction occurs, state 'No Reaction'. DMF = dimethyl if ormamide, CH_3 CN = acetonitrile