Question

Draw the intermediate and final organic structures

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Answer #1
Concepts and reason

The problem is based on the concept of epoxide ring opening in the presence of a base. In basic medium, epoxide undergo ring opening via SN2{S_{\rm{N}}}2 mechanism.

Fundamentals

Epoxides are three-membered ring structures which contain an oxygen atom at one vertex and two carbon atoms at other two vertices. The carbon atoms in epoxides ring are electrophilic and therefore, react with nucleophile which opens the strained ring.

An example of ring-opening of symmetrical epoxide is as follows:

WILL
CH3
Nu
Nu CH3
ОН
H3C
Nu CH3

In case of unsymmetrical epoxide ring, the nucleophile attacks from the less hindered side. An example of ring-opening of unsymmetrical epoxide is as follows:

Не
Nu
СН3
ОН
Nu
CHZ

The mechanism of the ring opening reaction is as follows:

=OH
NaOH
HTITii
H |||||
20H
H20
H0
Hillii
E

The reaction mechanism is as follows:

11月
a01月
- H50
HMM...
HO
HIHIM
SOH
11
:0:
H+

Ans:

The intermediate formed in the reaction is,

Hјни
ОН

The final product of the reaction is,

HY

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Draw the intermediate and final organic structures in the following two-step reaction, showing the correct stereochemistry.
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