Question

Chlorine is widely used to purify municipal water supplies and to treat swimming pool water. Suppose that the volume of a particular sample of Cl2 gas is 8.70 L at 890 torr and 24 ∘C.

1. How many grams of Cl2 are in the sample?

2. What volume will the Cl2 occupy at STP?

3. At what temperature will the volume be 15.50 L if the pressure is 875 torr?

4. At what pressure will the volume equal 7.00 L if the temperature is 55 ∘C?

Answer 1

1. PV = nRT . n = PV RT P = 890 tonn = 760 - 890 atm V = 8.70L T=(24+273)k = 297K R = 0.0821 lit atm motky in = 890 X 8.70 760 X 0·0821x297 = 0.4178 ł 0.42 mole 2 At STP T = 273K P = 760 fohp Vi=? Vi = Pz Ve TI = 890 *8.7 x 273 PIT 760× 297 = 9.3648 ł 9.36 litre

30 PIVI = P V2 . Ti Te P = 890 tonn P = 875 toan. V = 8.7 lit V2 = 15.50 Lit T = 297K T = ? P₂ V₂ TL PVL - 875 X 15.50 X 297 890 807 = 520.2198 7 520.22K T = 4. P = 890 torr v =8.7 lit T = 2976 1 .: P2 = PiVi Tz TV2 P = ? V2 = 7.00lt T2 = (55+273)K = 3284 - 890 8.7 x 328 298 x 7.00 = 1221.598tohl a 1221.60 forr.