1-
Exercise 11-06
Crane Company purchased equipment for $192,000 on October 1,
2020. It is estimated that the equipment will have a useful life of
8 years and a salvage value of $12,000. Estimated production is
36,000 units and estimated working hours are 20,000. During 2020,
Crane uses the equipment for 500 hours and the equipment produces
1,000 units.
Compute depreciation expense under each of the following methods.
Crane is on a calendar-year basis ending December 31.
(Round rate per hour and rate per unit to 2 decimal
places, e.g. 5.35 and final answers to 0 decimal places, e.g.
45,892.)
(a) |
Straight-line method for 2020 |
$enter a dollar amount | ||
---|---|---|---|---|
(b) |
Activity method (units of output) for 2020 |
$enter a dollar amount | ||
(c) |
Activity method (working hours) for 2020 |
$enter a dollar amount | ||
(d) |
Sum-of-the-years'-digits method for 2022 |
$enter a dollar amount | ||
(e) |
Double-declining-balance method for 2021 |
$enter a dollar amount |
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Crane Company | ||
Cost of Equipment | 192,000.00 | A |
Residual Value | 12,000.00 | B |
Depreciable Value | 180,000.00 | C=A-B |
Answer a | ||
Straight Line Method | ||
Depreciable Value | 180,000.00 | See C |
Life | 8.00 | D |
Annual depreciation | 22,500.00 | E=C/D |
Purchased on Oct 1, 2020 | ||
Depreciation for 2020 (months) | 3.00 | F |
Depreciation expense for 2020 | 5,625.00 | G=E/12*F |
Answer b | ||
Units of output Method | ||
Depreciable Value | 180,000.00 | See C |
Life (Units) | 36,000.00 | H |
Depreciation per unit | 5.00 | I=C/H |
Production in 2020 | 1,000.00 | J |
Depreciation expense for 2020 | 5,000.00 | K=I*J |
Answer c | ||
Working hours Method | ||
Depreciable Value | 180,000.00 | See C |
Life (hours) | 20,000.00 | L |
Depreciation per hour | 9.00 | M=C/L |
Hours used in 2020 | 500.00 | N |
Depreciation expense for 2020 | 4,500.00 | O=M*N |
C | P | Q=C*P | ||||||
Answer d | Table | Depreciable Value | Remaining life | Depreciable fraction | Depreciable Expense | |||
Sum-of-the-years'-digits method | Year 2020 | 180,000.00 | 8.00 | 8/36 | 40,000.00 | |||
Depreciable Value | 180,000.00 | See C | Year 2021 | 180,000.00 | 7.00 | 7/36 | 35,000.00 | |
Life (years) | 8.00 | See D | Year 2022 | 180,000.00 | 6.00 | 6/36 | 30,000.00 | |
Refer table in the right side. | Year 2023 | 180,000.00 | 5.00 | 5/36 | 25,000.00 | |||
That is annual depreciation. | Year 2024 | 180,000.00 | 4.00 | 4/36 | 20,000.00 | |||
But equioment purchased on Oct 1 | Year 2025 | 180,000.00 | 3.00 | 3/36 | 15,000.00 | |||
Depreciation for 2020 (months) | 3.00 | See F | Year 2026 | 180,000.00 | 2.00 | 2/36 | 10,000.00 | |
Annual Depreciation for 2020 | 40,000.00 | Z | Year 2027 | 180,000.00 | 1.00 | 1/36 | 5,000.00 | |
Depreciation expense for 2020 | 10,000.00 | AA= Z/12*F | 36.00 | 180,000.00 | ||||
Remaining will be allicated to 2021 | 30,000.00 | AB= Z-AA | ||||||
Annual Depreciation for 2021 | 35,000.00 | AC | ||||||
3 months deprciation | 8,750.00 | AD= AC/12*F | ||||||
Depreciation expense for 2021 | 38,750.00 | AE= AB+AD | ||||||
Remaining will be allicated to 2022 | 26,250.00 | AF=AC-AD | ||||||
Annual Depreciation for 2022 | 30,000.00 | AG | ||||||
3 months deprciation | 7,500.00 | AH=AG/12*3 | ||||||
Depreciation expense for 2022 | 33,750.00 | AI= AF+AH |
Answer e | ||
Double Declining Method | ||
Cost of Equipment | 192,000.00 | See A |
Life | 8.00 | See D |
Annual depreciation | 24,000.00 | R=A/D |
Depreciation rate | 12.50% | S=R/A |
Double Depreciation % | 25.00% | T=S*2 |
Annual depreciation for 2020 | 48,000.00 | U=A*T |
Purchased on Oct 1, 2020 | ||
Depreciation for 2020 (months) | 3.00 | V |
Depreciation expense for 2020 | 12,000.00 | W=U/12*V |
Book value in 2021 | 180,000.00 | X=A-W |
Depreciation expense for 2021 | 45,000.00 | Y=X*T |
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