Solution:-
7.1)
Mean = 591, S.D = 42
a) The scores on GMAT entrance exam are continuous variable.
b) The probability that scores will be less than 600 is 0.5848.
x = 600
By applying normal distribution:-
z = 0.2143
P(z < 0.2143) = 0.5848
c) The probability that scores from sample of 50 will be less than 600 is 0.9351.
x = 600
By applying normal distribution:-
z = 1.515
P(z < 1.515) = 0.9351
d) The probability that scores from sample of 100 will be less than 600 is 0.9839.
x = 600
By applying normal distribution:-
z = 2.143
P(z < 2.143) = 0.9839
plz show all work... Exercises for Chapter 7: Sa mpling Distributions I entrance exam at an...
show work plz ruckload of 5000 electric drills. Exercise 7.2: The warehouse for a hardware store chain has just received a t Before accepting the shipment, the purchasing manager in for testing. He intend if the mean consumption for the sample is greater than 300 watts as listed on the product sists that a sample of the drills be randomly selected s to measure the maximum power consumption of each drill. He will reject the shipment ipment is the manufacturer's...
please be clear and solved all Let X and Y be two Independent random variables such that V(X) =1 and V(Y) =2. Then V(3X-2Y+5) is equal: a. 25 b. 20 17 d. 15 C. O a d Let X and Y be two random variables such that E(X) = 2, E(Y) = 5 and E(XY)=7. The covariance of (X, Y) is equal to: a. 17 b. 14 c. 3 d. -3 a O с Od Question 3* 10 points Light...
the following questions are either true or false answers 1. The Central Limit Theorem allows one to use the Normal Distribution for both normally and non-normally distributed populations. 2. A random sample of 25 observations yields a mean of 106 and a standard deviation of 12. Find the probability that the sample mean exceeds 110. The probability of exceeding 110 is 0.9525. 3. Suppose the average time spent driving for drivers age 20-to-24 is 25 minutes and you randomly select...
Let X and Y be two Independent random variables such that V(X) =1 and V(Y) =2. Then V(3X-2Y+5) is equal: a. 25 b. 20 17 d. 15 C. O a d Light bulbs are tested for their life-span. The probability of rejected bulbs is found to be 0.04. A random sample of 15 bulbs is taken from stock and tested. The random variable X is the number of bulbs that are rejected. The probability that 2 light bulbs in the...
Please answer the marked questions.......... Please show your work............. that all young adult men is greater the IC than 50 min d the 65 74 66 37 45 68 64 50 48 65 58 55 52 63 59 57 74 65 the 11.38 1138 The club professional at a difficul that his course is so tough that t course boasts average golfer loses a dozen or more golf balls d ng a round of golf. A dubious golfer sets out...
problems 4, 5, 6, 11 and 13 If the population standard deviation was doubled to 10.4 and the level of confidence remained at 90%, what would be the new margin of error and confidence interval Margin of error, E. Confidence interval: 20.11<x<34.31 O Did the confidence interval increase or decrease and why? increase 4. Definition of Confidence Intervals (Section 6.1) Circle your answer, True of False. • A 99% confidence interval means that there is a 99% probability that the...
Write solutions legibly, and show all work. Walk the reader through your thought process, using English words when necessary. 1. Recall question 2 of the previous homework – We draw 6 cards from a 52 card deck and let X = the number of heart cards drawn. You already found the pmf back then. You’re allowed to use it here without re-deriving it. a. What is the expected value of X? b. What is the variance of X? What is...
photos for each question are all in a row (1 point) In the following questions, use the normal distribution to find a confidence interval for a difference in proportions pu - P2 given the relevant sample results. Give the best point estimate for p. - P2, the margin of error, and the confidence interval. Assume the results come from random samples. Give your answers to 4 decimal places. 300. Use 1. A 80% interval for pı - P2 given that...