Starting material/product |
Molecular weight |
Amount taken |
Moles |
Equivalent used |
Acetophenone |
120 (d=1.03) |
125 g |
1.04 |
1 |
Ammonium formate |
63 |
75 g |
1.19 |
1.14 |
Phenylethylamine |
121.18 (d=0.964) |
126.22 g |
||
120 gm of Acetophenone gives 121.18 gm of Phenylethylamine
Then 125 gm of Acetophenone gives x gm of Phenylethylamine
Theoretical yield of the given reaction = (125*121.18)/120 = 126.22 g
126.22 gm of final product can be obtained from the given reaction
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