Question

PRACTICE IT Use the worked example above to help you solve this problem. Consider the figure below, where = 5.12 kg, m2 = 2.58 kg, m3 = 4.05 kg, d, = 1.37 m. Treat the objects as point 0.423 m, and d2 m1 particles. т, 1.00 m т, т, т, m2 d, 0.500m m3 Б (a) Three particles are located in a coordinate system shown in Figure (a). Find the center of gravity (b) How does the answer change if the object on the left is displaced upward by 1.00 m and the object on the right is displaced downward by 0.500 m (Figure (b))? m m

Answer 1

. a dat ^ Given mi [m2 m3 mi=5.12kg M2=2.58 kg 3=4.05 kg di=0.423m d2=1.37m xc.G = midit m2(0)+ Mzd mitmz+3 = (5.12) (-0.423) + 0 +64.0541.37) 5,12+2.58 +4:05 = 0.287 m ausim Y me .. Toism XcoG = 0.287 in dz YC.G = (m) (1)+(m2)(0) +(m3)(-0.5) mitm2t3 = (5.12)(1) + 0 +(4.05)(-0.5) 5,12 +2.58 +4.05 = 0.263 m oi kc. G=0,287m ? Aus YC.G=0,263m )