Question

Problem #4 In the diagram below, a 3.00 kg mass is attached to a rod 2.00 m long by two strings which are each 1.50 m in length. The rod completes one turn every 1.40 s, so that the mass completes one turn every 1.40 s. (a) Find the radius of the circle traced out by the mass. (b) Draw a free-body diagram for the ball, including all force vectors and the acceleration vector. (c) Find the tension in the upper string and in the lower string.

Answer 1

a) Radius of the circle in - R=(1-5) ² (DE (R = 1.118 m) Fra Ang 15m Free body diagram fo ball 1.5m 5 mo Tising - R=1:18m Ortant (418) 1 41.810 T2.che Ketenay tamaa 1 T2 Sino angular speed wit 21 = 4.486 rad's tangential Speed v=Rw Va 1.118x4.486= 5.02 m/s ni centripetal acceleration aga 225 m/s2 & Fxz - ma (T14T2) ge = mar (nazar) may - 3X 22- 5 90.544 99 09 (41-81) 90.220 Tismo - Tasmo - ngat T-12. = = 19.60 55.072N Efy so =) - 0103 - 27= 110.149 s) (13 uppershing a lower Shring ower string T2 = 90.544-55-072 52. z 35.472N