Question

8. An electric heater with a resistance of 14.4 Ω is designed to operate at 120 V. What is its power? 1400 W 0150w 0240 W O 1000 w
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Answer #1

Power of heater = V2/R

here V is voltage and R is resistance so

P = (120)2/14.4

P = 1000 watt

correct answer is (D) 1000 W

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