Question

| Take Test: Homework 1-1-(2019 -Courses-Blackboard Learn rk" (201901-MAT258-8 × ㅮ Continue: Homework 1-1-(2016 × X https://oswego open suny.edu/webapps/assessment take/takeisp?course assessment id=-710971 &course id-381031&content id-_1112195 18questio ! à Moving to another question will save this response tion 2 Travelers pay taxes for flying, car rentals, and hotels. The following data represent the total travel tax for a 3-day business trip in eight randomly selected cities 67.81 78.69 68.99 84.36 80.24 86.14 101.27 99.29 Use Minitab Express to construct the following confidence intervals. Report your answers rounded to three decimal places, where applicable. a) We are 90% confident that the mean travel tax for a 3-day business trip to an American city is between S b) We are 90% confident that the standard deviation travel tax for a 3-day business trip to an American city is between S and S and S A Moving to another question will save this response 0 Type here to search

Answer 1

Solution:-

a) 90% confidence interval for the mean travel tax for a 3 day business trip is C.I = (77.184, 89.514).

$C.I = \bar{x}\pm t_{\alpha /2}\ast \frac{\sigma }{\sqrt{n}}$

C.I = 83.34875 + 1.415*4.35706

C.I = 83.34875 + 6.1652

C.I = (77.184, 89.514)

b) 90% confidence interval for standard deviation travel tax for a 3 day business trip is $8.692< \sigma < 22.149$ .

$\sqrt{\frac{s^{2}(n-1)}{\chi^{2}_{\alpha /2} }}< \sigma < \sqrt{\frac{s^{2}(n-1)}{\chi^{2}_{1-\alpha /2} }}$

$\sqrt{\frac{(12.323631)^{2}(8-1)}{14.07}}< \sigma < \sqrt{\frac{(12.323631)^{2}(8-1)}{2.167 }}$

$8.692< \sigma < 22.149$