Question

Tarzan with a mass of 56.2 kg stands atop a branch in the African rain forest. He grabs this 28.7 m long vine and swings out. Initially the vine made an angle of 33.0° to the vertical. a.) What is the difference in height from where he starts to the bottom of his swing? b.) How fast will he be traveling when he reaches the bottom of his swing?

Answer 1

$Cos\theta =(28.7-h)/28.7$

$28.7Cos33=(28.7-h)$

$24.07=(28.7-h)$

(a)ANSWER: $h=4.63m$

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When Tarzan reaches bottom of swing ,all potential energy will be converted to kinetic energy

$KE=PE$

$1/2mv^{2}=mgh$

$1/2v^{2}=gh$

$v=\sqrt{2gh}$

$v=\sqrt{2*9.81*4.63m}$

(b)ANSWER: $v=9.53m/s$

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