Q.6) Let X = Yield Strength ( ksi ) and f = frequency
X | f | X * f |
---|---|---|
72 | 1 | 72 * 1= 72 |
69 | 3 | 69 * 3 = 207 |
65 | 2 | 65 * 2 = 130 |
64 | 2 | 64 * 2 = 128 |
58 | 2 | 58 * 2 = 116 |
Expected value of X is,
The approximate mean yield strength of the population from which the samples were taken is 65.3
Answer: a) 65.3
6) 10 samples of 4140 steel (as received) were tensile tested from a population of 1000+...
10 samples of 4140 steel (as received) were tensile tested from a population of 1000+ and the yield strengths had a frequency distribution as shown: Yield Strength (ksi Frequency 72 69 65 64 58 What is the approximate standard deviation of the yield strengths of the which the samples were taken? a) 4.43 b) 4.67 c) 4.76 d) 5.32
No excel, show work please. 10 samples of 4140 steel (as received) were tensile tested from a population of 1000+ and the yield strengths had a frequency distribution as shown: Yield Strength (ksi Frequency 72 69 65 64 58 What is the approximate standard deviation of the yield strengths of the which the samples were taken? a) 4.43 b) 4.67 c) 4.76 d) 5.32
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