Question

9. In a hydrogen atom a single electron orbits a proton at a radius of 0.05 nm. a. What’s the potential at this distance from the proton? b. How much electric energy is stored in the atom, in both eV and J?

Answer 1

Summary of answer:-Potential at a distance r due to a charge q is given by-

   $V=\frac{kq}{r}$

where k= electrical constant=9x10^9 nm²/C²

and potential energy due to system of two charges is given by-

$U=\frac{kq_{1}q_{2}}{r}$

also

$1ev=1.6\times 10^{-19}joule$