The operating potential difference of a light bulb is 120 V. The power rating of the...

Question

Question

The operating potential difference of a light bulb is 120 V. The power rating of the bulb is 90 W.

(a) Find the current in the bulb. A

(b) Find the bulb's resistance.

Answer 1

Answer #1

a)

P = Vi

90 = 120 i

i = 0.75 A

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b).

R = V/i = 120 / 0.75

R = 160 ohm

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Comment in case any doubt, will reply for sure . Goodluck

Answer 2

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