Question

Question 8 of 18 (1 point) Attempt 1 of Unlimited View question in a popur! 72 Section Exerci Online courses: A sample of 269 students who were taking online courses were asked to describe their overall impression of online learning on a scale of 1-7, with 7 representing the most favorable impression. The average score was 5.77, and the standard deviation was 0.98. (a) Construct a 90% confidence interval for the mean score. (b) Assume that the mean score for students taking traditional courses is 5.61. A college that offers online courses claims that the mean scores for online courses and traditional courses are the same. Does the confidence interval contradict this daim? Explain. Part: 0/2 Part 1 of 2 (a) A 90% confidence interval for the mean score is < < (Round the answers to at least two decimal places.)

Answer 1

a) At 90% confidence level, the critical value is z_0.05 = 1.645

The 90% confidence interval is

T士 20.05 *

= 5.77 +1.645 * 0.98 269

-5.7740.0983

-5.6717.5.8683

b) Since the interval does not contain 5.61, so the confidence interval contradict the claim.