Question

You roll a six-sided die. Find the probability of each of the following scenarios. (a) Rolling a 6 or a number greater than 3 (b) Rolling a number less than 4 or an even number (c) Rolling a 4 or an odd number (a) P(6 or number> 3)- (Round to three decimal places as needed) (b) P/1 or 2 or 3 or 4 or 6)-( Round to three decimal places as needed.) (c) P(4 or 1 or 3 or 5) (Round to three decimal places as needed.)

Answer 1

Solution:-

1)

(a) P(6 or number > 3) = (1/6) + (3/6) = 0.667

(b) P(1 or 2 or 3 or 4 or 6) = 5/6 = 0.833

(c) P(4 or 1 or 3 or 5) = 4/6 = 0.667

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2) The value of z-score is -1.18

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3) Given that n = 27, X = 34.9, s = 7.2

df = n-1 = 26

90% confidence interval for the t = 1.706

90% confidence interval for the population mean = X +/- t*s/sqrt(n)
= 34.9 +/- 1.706*7.2/sqrt(27)
= 32.536 , 37.264
= 32.5 , 37.3

Margin of error = 1.706*7.2/sqrt(27) = 2.4

=> option D.