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Chapter 21 Electric Field Exercise 21.45- Enhanced-with Solution You may want to review (Pages 609 704) two electrons are each 1.40-10-10m trom a protion, as shown in the tgure, tind the magnitude of the net electrical fonce they wilexert on the proton (Fioue 1) For related probiem-soving sps and strategies, you may wart to viewa Incorrect Try Again; 5 attempts remaining Enter your answer as an angle measured relative to the line connecting the proton and the right electron with countereleekwise being positve Figure 65.0 Return to Assignment Provdide Fec
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belutton Part A he ferce en the photon due to nigat handed electんon is, f = Kgeqr 虎 -19 (1. 40 x 10-i0 合 う = 1.175510 20 4x10-8 % tind the terre en the eten, dire to ahove etectren hesolve the vectos Fe(4.967920791火10-92 + 1.065374052. X108 J)N = (1.672302293 1.015ろ74052]) x10 2 + The magnibude the net fer うF- d (1.672.302283x10, s )) + (1,06 5571052 xtory 1.982830501 10-8 N tar(은) Pant e Ota1, 065374052 K1o f. 6 7 2302283 x to 。 32.50000001 θ= 32.5°

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