Question

Concentration of HCL. Im suppose to use the number from the pervious problem to solve this one but im not sure how.

Calculations for Molarity of the Molarity. of Molarity of the NaOH Solution for each Run and the .35489 (204.9.fol.02 ) 210.079 wil net wa)(0242loose mobile 3533 g 204.22g/mol.02142) 10.081 milk Average= (.079+.082+.081/3 +0.081 mol/d Determination of the Concentration of an HCI Solution UNKNOWN NUMBER_1 Trail 1 Trail 2 1 10.ome Trail 3 10.0mL 10.0mL 0.00ML 0.00ML 0.00mL 12.0mL 12.4mL 12.5ML Volume of HCI mL) Initial Volume of burette (mL) Final Volume of burette (mL) Volume of NaOH used (mL) Concentration of HCI moles/L) 12. UML 12.4 ML 12.5 mL Average Concentration of HCl (mol/L):

Answer 1

To calculate the concentration of HCl, we just have to use the equation, where, V represents the volume of the species mentioned and S represents the concentration of the species in mol/L.

VuqSug = VNqOHSN OH

Again as HCl and NaOH reacts in 1:1 ratio, the

no. of moles of NaOH = no. of moles of HCl

Concentration of HCl ($S_{HCl}$)

Strial1,Hci = (0.0126 x 0.081)/0.01 = 0.102M

STrial2,HC1 = (0.0124 x 0.081)/0.01 = 0.1M

STria/3, HCI = (0.0125 x 0.081)/0.01 = 0.101M

hence, Average concentration of HCl =(0.102+0.1+0.101)/3=0.101 M.