1)
Increasing Temperature will shift the reaction in a direction which absorbs heat as per Le chatelier Principle
Forward reaction is endothermic in nature
hence, forward reaction will be favoured
So, Equilibrium moves to product side
So, concentration of H2 will increase
Answer: T
2)
Increasing pressure will shift the reaction in a direction which have lesser gaseous molecules as per Le chatelier Principle
Here, number of gaseous molecules is same on both side
So equilibrium will not be effected
So, No effect on equilibrium
So, concentration of H2 will not change
Answer: F
3)
Increasing volume will decrease the pressure which in turn shift the reaction in a direction which have greater gaseous molecules as per Le chatelier Principle
Here, number of gaseous molecules is same on both side
So equilibrium will not be effected
So, No effect on equilibrium
So, concentration of H2 will not change
Answer: F
4)
Adding reactant will shift the reaction in the direction of product as per Le chatelier Principle
So, Equilibrium moves to product side
So, concentration of H2 will increase
Answer: T
5)
Removing product will shift the reaction in the direction of product as per Le chatelier Principle
So, Equilibrium moves to product side
So, concentration of H2 will increase
Answer: T
Consider the following system at equilibrium where K. = 1.80x10-2 and AH° = 10.4 kJ/mol at...
Consider the following system at equilibrium where Kc = 1.80×10-2and H° = 10.4 kJ/mol at 698 K. 2 HI (g) -->H2(g) + I2(g) The production of H2(g) is favored by: Indicate True (T) or False (F) for each of the following: ___TF 1. increasing the temperature. ___TF 2. increasing the pressure (by changing the volume). ___TF 3. increasing the volume. ___TF 4. removing HI . ___TF 5. adding I2. Consider the following system at equilibrium where Kc = 55.6 and...
Consider the following system at equilibrium where Kc = 1.80×10-2and delta H° = 10.4 kJ/mol at 698 K. 2 HI (g) goes to H2(g) + I2(g) The production of H2(g) is favored by: Indicate True (T) or False (F) for each of the following: ___TF 1. increasing the temperature. ___TF 2. increasing the pressure (by changing the volume). ___TF 3. increasing the volume. ___TF 4. removing HI . ___TF 5. removing I2.
Consider the following system at equilibrium where K - 1.29x10- and AH = 108 kJ/mol at 600 K. COC12() CO(g) + Cl2 ) The production of CO (g) is favored by: Indicate True (T) or False (F) for each of the following: 1. increasing the temperature. 2. increasing the pressure (by changing the volume). 3. increasing the volume. 4. removing COCI2. 5. removing Cl2 Submit Answer Retry Entire Group 1 more group attempt remaining Consider the following system at equilibrium...
Consider the following system at equilibrium where K. = 34.5 and AH° = -198 kJ/mol at 1150 K. 2 SO2 (g) + O2(g) 2 S03 (g) The production of Soz (g) is favored by: Indicate True (T) or False (F) for each of the following: 1. decreasing the temperature. 2. increasing the pressure (by changing the volume). 3. decreasing the volume. 4. adding SO3 5. removing 02
Consider the following system at equilibrium where K. -2.90x10-2 and AH° = 198 kJ/mol at 1150 K. 2 S03 (9) 2 SO2 (g) + O2 (g) The production of SO2 (g) is favored by: Indicate True (T) or False (E) for each of the following: 1. decreasing the temperature. 2. increasing the pressure (by changing the volume). 3. decreasing the volume. 4. removing S03 5. adding 0,
Consider the following system at equilibrium where K. = 9.52x10-2 and AH° = 18.8 kJ/mol at 350 K. CH4 (g) + CCl4 (g) – 2 CH2Cl2 (g) The production of CH2Cl2 (g) is favored by: Indicate True (T) or False (F) for each of the following: - 1. decreasing the temperature. 2. decreasing the pressure (by changing the volume). 3. increasing the volume. 4. adding CH2Cl2 - 5. adding CC14 -
Consider the following system at equilibrium where AH° = 10.4 kJ, and K. -1.80x10-2, at 698 K. 2HI(g) 2 H2(g) + 12() When 0.24 moles of H2(g) are added to the equilibrium system at constant temperature: The value of K. The value of Qc В к The reaction must run in the forward direction to restablish equilibrium run in the reverse direction to restablish equilibrium. remain the same. It is already at equilibrium. The concentration of I, will
Consider the following system at equilibrium where AH° ° = 10.4 kJ, and Kc = 1.80x10-2, at 698 K. 2HI(g) H2(g) + 12(g) When 0.25 moles of H2(g) are removed from the equilibrium system at constant temperature: The value of Kc The value of Qc AK The reaction must Crun in the forward direction to restablish equilibrium. run in the reverse direction to restablish equilibrium. remain the same. It is already at equilibrium. The concentration of 12 will
Consider the following system at equilibrium where Kc = 7.00×10-5and H° = 182 kJ/mol at 673 K. NH4I (s) - NH3(g) + HI (g) The production of NH3(g) is favored by: Indicate True (T) or False (F) for each of the following: ___TF 1. increasing the temperature. ___TF 2. decreasing the pressure (by changing the volume). ___TF 3. increasing the volume. ___TF 4. adding NH4I . ___TF 5. removing HI
Consider the following system at equilibrium where Kc = 77.5 and H° = -108 kJ/mol at 600 K. CO (g) + Cl2 (g) COCl2 (g) The production of COCl2 (g) is favored by: Indicate True (T) or False (F) for each of the following: 1. decreasing the temperature. 2. increasing the pressure (by changing the volume). 3. increasing the volume. 4. adding COCl2 . 5. removing Cl2 .