Question

2 Mechanical equilibrium 200N 200 N 250N Ws? (10 pts) The sketch shows a painters staging in mechanical equilibrium. The person in the middle weighs 250N, and the tensions in each rope are 200N. What is the weight of the staging (the horizontal platform)?
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Answer #1

For equilibrium,

sum of the forces must be equal to zero. That is,

Sum of forces = 0

=> 200 + 200 - 250 - W = 0

=> W = 150 N (answer)

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