The activation energy dG for the step C to B
= Energy of C - Energy of 2nd activated state
= (7 - 24) kcal/mol
= -17 kcal/mol
Overall energy change for the process B to A
= Energy of B - Energy of A
= (12 - 5 ) = 7 kcal/mol
Activation energy for the step B to A
= ( 18 - 12 ) = 6 kcal/mol
Activation energy for the step B to C
= (24 - 12) = 12 kcal/mol
Since the step B to A has lower energy of activation than the step B to C; hence the step B to A is faster than B to C.
Refer 25 20 15 10 B C 0 Reaction progress Use the reaction energy diagram above...
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