E.C. A constant current was passed through a solution of Cut2 for 5.00 min. The cathode...

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Answer 1

Answer #1

hiver => t = 5 min = 5x60 = 300 sec - mas deposited E 1.242 mess deposited (m) :_CIE @= Wt. Cu valancy e = 63.5 = 31.75 am, S

Answer 2

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