Price of K = $6 and K is fixed .So FC = $(10)(6)=$60
Price of labor = $10 Because VC= AVC(TP)= wL
Now, we can see that When L=1, AVC = 5 And TP= 2 , so w = $10
K | L | TP= Summation of MP | MP=(Change in TP) | FC | VC= wL | TC=FC+VC | AFC= FC/TP | AVC= VC/TP | ATC= TC/TP | MC= (Change in TC/change in TP) |
10 | 0 | 0 | - | 60 | 0 | 60 | - | - | - | - |
10 | 1 | 2 | 2 | 60 | (5)(2)= 10 | 70 | 30 | 5 | 35 | 5 |
10 | 2 | 6 | 4 | 60 | 20 | 80 | 10 | 3.33 | 13.33 | 2.5 |
10 | 3 | 16 | 10 | 60 | 30 | 90 | 3.75 | 1.87 | 5.62 | 1 |
10 | 4 | 24 | 8 | 60 | 40 | 100 | 2.5 | 1.67 | 4.17 | 1.25 |
10 | 5 | 29 | 5 | 60 | 50 | 110 | 2.06 | 1.72 | 3.78 | 2 |
10 | 6 | 32 | 3 | 60 | 60 | 120 | 1.87 | 1.87 | 3.74 | 3.33 |
10 | 7 | 33 | 1 | 60 | 70 | 130 | 1.81 | 2.12 | 3.93 | 10 |
1. Price of L= $10. Hence,option(B) is correct.
2. When TP=32 , MP= 3 . Hence,option(D) is correct.
3. When L = 3 , ATC = $5.625. Hence, option(C) is correct.
4. If Pk changes to $8 , then marginal cost are not affected because MC only affected by changes in variable cost. Hence,option(A) is correct.
Table 1. Production and Counctions of Suppose is the feed input and the valable input. Price...
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I don't understand how there is a correct answer to this. I put everything into an excel file and each one of these would be changed. Table 1. Production and Cost Functions of a Firm Suppose K is the fixed input and the variable input. Price of K = $6; Price of L= ? TP MP Fc vc tc Arc Ave Arc MC 0 5.00 10 14 129 6 32 33 1. Refer to Table 1. Price of L =...
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