Question

Calculate the percent ionization of hydrazoic acid (HN3) in solutions of each of the following concentrations (Ka is given in Appendix D in the textbook).

Part A 0.406 M . Express your answer using two significant figures. TemplatesSymbols undoredoresetkeyboard shortcutshelp nothing   % %    SubmitRequest Answer Part B 0.118 M . Express your answer using two significant figures. TemplatesSymbols undoredoresetkeyboard shortcutshelp nothing   % %    SubmitRequest Answer Part C 4.03×10−2 M . Express your answer using two significant figures.

Answer 1

lonisation Per cant ot we ck uid s drazoi wiHL acid Ka value 19 x165. 1 dsS S in Ao ter dissauatinm e qui brum Can be wni Hew The ICE ta b le HN3 (a t ) N3 Cai3d Ca9) the onmoun O.406 +n diss ocia te s chenge EquiibniumC.u06-- + Ka 9X10-5 7 (d406-2 Compare wit ant brt Co bt yae K105 (11x105-4 x -19x10 5 f$55 X16 2 1 taken 2.7679 103 L H3at LN3 2.1679 x103 M JHNJionisedytoay .. o ni sation oN aud 27639 x10 3 o6817 %

N3 Can e Thi dissouo tion wniHen as equi ibnium t N3 Ca9 tH30f Ca 0 ICE fable +m +n Changes -n Equiu brium(0-ug-) underes amaunt of be the 1onisa ion NS CHNS Ka 1.9 x10-5 +qX165- 2.242 x16 pare wit ३ -19x105+ 31 -19X105 + t(1054-1.(-2-2421 2.9947x163 vah acem 2.936 2.3151 - 14878X163 14878 X103 m ovi Sa hon JN aud Xtro CHNSmiHa J. 1-4878 13 O 118 1.26

Ano de) the Snlsn2+ electrode to catho de) tha Cu cult graes eunit, eleetron h the erternal electrode t anode ridae S Snt ani ons at the Sa 14 IM f-e electrode fe Catons an d toards cathode maye ce 1cut e lectrde dissouation e auiubrium H3 Cam ae The We Hen N3 Ca H 30 can N3 Cay t0( CE lable IniHial 4.03X1 + Change + Equilibriun JtN3 oni ses. amaum CN3 3 19 5 9x165 F7.01x50h) 765 Co pare With autbnt =0 19x165 X15) 41- (-7+657 X10) 2.1 9x165 175 X103 Ve talee 86559 X104 EH3a N 8655 X10 CH3oised HN3 Inihu 86559 X1 s4 oni Sation 403 10 2.1478 7