if you have a mixture of 80g ethanol and 20g methanol. calculate mole fractions of each
Homework Answers
Molar mass of C2H5OH,
MM = 2*MM(C) + 6*MM(H) + 1*MM(O)
= 2*12.01 + 6*1.008 + 1*16.0
= 46.068 g/mol
Molar mass of CH3OH,
MM = 1*MM(C) + 4*MM(H) + 1*MM(O)
= 1*12.01 + 4*1.008 + 1*16.0
= 32.042 g/mol
n(C2H5OH) = mass/molar mass
= 80.0/46.068
= 1.7366
n(CH3OH) = mass/molar mass
= 20.0/32.042
= 0.6242
n(C2H5OH),n1 = 1.7366 mol
n(CH3OH),n2 = 0.6242 mol
Total number of mol = n1+n2
= 1.7366 + 0.6242
= 2.3607 mol
Mole fraction of each components are
X(C2H5OH) = n1/total mol
= 1.7366/2.3607
= 0.736
X(CH3OH) = n2/total mol
= 0.6242/2.3607
= 0.264
Answer:
Mole fraction of ethanol = 0.736
Mole fraction of methanol = 0.264
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