Question

2. A natural product (MW-150) distills with steam at a boiling temperature of 99°C at atmospheric pressure. The vapor pressure of water at 99°C is 733 mm Hg. a) Calculate the mass of the natural product that codistills with each gram of water at 99°C. (2 pts.) Po 7500- 53 bo 27 nm non 70 Pb - Pa se Plo b) How much water must be removed by steam distillation to recover this natural product from 0.5 g of a spice that contains 10% of the desired substance? (1 pt)

Answer 1

. This is the basis for the calculations Pa males (a) (Pb moles (6) let use moles (as as the natural product Paz 760-733 =27mm Pb = 733 mm moles (6) = 1.00 g 0.055 moles 18 g/mol Molt fata oroador 27 = moles (9) 733 0.055 males (a) - 0.00 203 male maiss 0.00 203 x 150 g/may = 0.304 g 2 0.500 g spice x 0.10 g (a spice = 0.050 g (a) 0.050 g (o) x Image - 0.000333 moles (as 150g 0.00033 3 males (a) x 733 -0.00904 molu Hao 0.00904 males(b) x 18.02 g molib 20.162 9 H2O