b)
probability = | P(0.35<X<0.65)= | (0.65-0.35)/(1-0)= | 0.3000 |
c)
probability = | P(X<0.2)= | (0.2-0)/(1-0)= | 0.2000 |
d)
probability = | P(X>0.6)= | 1-P(X<0.6)= | 1-(0.6-0)/(1-0)= | 0.4000 |
e)
below are 50 random number:
no. | x |
1 | 0.8497 |
2 | 0.1046 |
3 | 0.2767 |
4 | 0.9407 |
5 | 0.4268 |
6 | 0.7556 |
7 | 0.1494 |
8 | 0.8011 |
9 | 0.6731 |
10 | 0.2214 |
11 | 0.4765 |
12 | 0.8030 |
13 | 0.1496 |
14 | 0.3108 |
15 | 0.0323 |
16 | 0.3198 |
17 | 0.9194 |
18 | 0.0179 |
19 | 0.4523 |
20 | 0.0653 |
21 | 0.6197 |
22 | 0.9166 |
23 | 0.8568 |
24 | 0.8315 |
25 | 0.2796 |
26 | 0.7407 |
27 | 0.7759 |
28 | 0.4637 |
29 | 0.0878 |
30 | 0.6573 |
31 | 0.2277 |
32 | 0.0947 |
33 | 0.8396 |
34 | 0.7303 |
35 | 0.2456 |
36 | 0.6511 |
37 | 0.7633 |
38 | 0.4805 |
39 | 0.8084 |
40 | 0.3861 |
41 | 0.2815 |
42 | 0.3556 |
43 | 0.9330 |
44 | 0.6021 |
45 | 0.0902 |
46 | 0.4822 |
47 | 0.7639 |
48 | 0.2476 |
49 | 0.4452 |
50 | 0.6749 |
f)
mean =0.5016
standard deviation =0.2890
(b) What is the probability of generating a random number between 0.35 and 0.65? (c) What...
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