Question

A mass of 397 g is attached to a spring and set into simple harmonic motion with a period of 0.246 s. If the total energy of the oscillating system is 5.94 J, determine the following. (a) maximum speed of the object 6.49 When is the total energy of the mass-spring system equal to the kinetic energy of the mass? m/s (b) force constant N/m (c) amplitude of the motion Additional Materials Reading

Answer 1

A)

Energy, E = 0.5 mv^2

5.94 = 0.5 x 0.397 v^2

Velocity, v = 5.47 m/s

B)

Angular velocity, w = 2 pi/T

w = 2 pi/0.246 = 25.54 rad/sec

Force constant, k = mw^2

k = 0.397 x 25.54^2 = 258.99 N/m

C)

E = 0.5 kA^2

5.94 = 0.5 x 0.397 x 25.54^2 A^2

Amplitude, A = 0.214 m

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