Answer - Find Oxidation states for the highlighted elements,
For H3O+ (aq)
We know that,
Oxidation State of H = +1
So,
3 * Oxiadation State of H + oxidation state of O = +1
So, Oxidation State of O = +1 - (3*1)
Oxidation State of O in H3O+= -2
For CHCl3 (l)
We know that,
Oxidation State of H = +1 and of Cl = -1
So,
Oxidation state of C + oxidation state of H + (3 * oxidation state of Cl) = 0
So, Oxidation state of C in CHCl3 = 0 - (1) - (3 *-1)
Oxidation state of C in CHCl3 = +2
For Cu2O (s)
We know that,
Oxidation State of O = -2
So,
2 * Oxidation state of Cu + oxidation state of O = 0
So, 2 * Oxidation state of Cu [Cu2]in Cu2O = 0 - (-2)
Oxidation state of Cu2 in Cu2O = +2 [Answer]
It is confusing as the highlighted element is Cu2 not Cu.
But if is misprint then the oxidation state of Cu in Cu2O is +1. [Answer]
For Br2 (g)
We know that, oxidation number in elemental state of any element is ZERO.
So, Oxidation State of Br in Br2 is 0. [Answer]
Some chemical reactants are listed in the table below. Complete the table by filling in the...
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