A rock is dropped from rest. It hits the ground after 16.4 seconds. What was the...

Question

Question

A rock is dropped from rest. It hits the ground after 16.4 seconds. What was the initial height of the rock, in km?

Answer 1

Answer #1

By using,

h = ut + (1/2)at^2

= 0 + 0.5*9.8*(16.4)^2

= 1317.904 m

= 1.32 km

Answer 2

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