In this case only velocity along y will change
No change in velocity along x and z
velocity along y will be=14-gt
=14-10(.2)
=12m/s
(g=10m/s^2)
Velocity after 0.2s=(-9,12,-4)m/s
b)initial velocity of the ball
c)final position of the ball
initial position of the ball=7,0,-8
final position of the ball along x=7-9*.2
=7-1.8=5.2m
final position of the ball along y=14t-1/2gt^2
=14*.2-5*.2*.2
=2.8-.2
=2.6m
final position of the ball along z=-8-4*.2
=-8.8
final position(5.2,2.6,-8.8)
initial position(7,0,-8)
total displacement=3.26
Total time=.2s
Avg velocity=3.26/.2
=16.3m/s
d)final position(5.2,2.6,-8.8)
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