+ 0/8 points Previous Answers Alpha particles of kinetic energy 4.80 MeV are scattered at 90°...
Alpha particles of kinetic energy 6.4 MeV are incident at a rate of 3.2 107 per second on a gold foil of thickness 3.2 10-6 m. A circular detector of diameter 1.0 cm is placed 13 cm from the foil at an angle of 30° with the direction of the incident alpha particles. At what rate does the detector measure scattered alpha particles? (The molar mass of gold is 197.0 g/mol and its density is 19.3 g/cm3.) Alpha particles of...
If the alpha particles have an initial kinetic energy of 7.7 MeV, then assuming a head-collision between an alpha particle (helium nucleus with +2e charge) and a gold nucleus (79 protons, so +79e charge), and using conservation of energy at the point of closest approach when all of the alpha particle's kinetic energy is converted to electric potential energy, calculate the approximate distance of closest approach (and thus coarsely estimate the size of the nucleus)
Alpha particles of kinetic energy 6.8 MeV are incident at a rate of 2.9 x 107 per second on an aluminum foil of thickness 2.9 x 10-6 m. A circular detector of diameter 1.0 cm is placed 14 cm from the foil at an angle of 30° with the direction of the incident alpha particles. At what rate does the detector measure scattered alpha particles? (The molar mass of aluminum is 27.0 g/mol and its density is 2.7 g/cm3.) s-1
Alpha particles of kinetic energy 6.8 MeV are incident at a rate of 2.9 x 107 per second on an aluminum foil of thickness 2.9 x 10-6 m. A circular detector of diameter 1.0 cm is placed 14 cm from the foil at an angle of 30° with the direction of the incident alpha particles. At what rate does the detector measure scattered alpha particles? (The molar mass of aluminum is 27.0 g/mol and its density is 2.7 g/cm3.) s-1
In Rutherford's scattering experiments, alpha particles (charge = +2e) were fired at a gold foil. Consider an alpha particle with an initial kinetic energy K heading directly for the nucleus of a gold atom (charge =+79e). The alpha particle will come to rest when all its initial kinetic energy has been converted to electrical potential energy. Find the distance of closest approach between the alpha particle and the gold nucleus for the case K = 3.5 MeV
An alpha particle with a kinetic energy of 12.0 MeV makes a head-on collision with a gold nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the gold nucleus remains stationary and that it may be treated as a point charge. A gold nucleus has 79 protons, and an alpha particle is a helium nucleus consisting of two protons and two neutrons. The mass of an alpha particle is 6.64424 x 10-27 kg....
An alpha particle with a kinetic energy of 10.0 MeV makes a head-on collision with a gold nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the gold nucleus remains stationary and that it may be treated as a point change. The atomic number of gold is 79, and the alpha particle is a helium nucleus consisting of 2 protons and 2 neutrons).
In 1910 Rutherford performed a classic experiment in which he directed a beam of alpha particles at a thin gold foil. He unexpectedly observed a few of the particles scattered almost directly backward. This result was not consistent with then current models of atomic structure and led Rutherford to propose the existence of a very dense concentration of positive charge at the center of an atom—the atomic nucleus. The alpha particle has a charge of +2e and the gold nucleus...
Each a particle in a beam of a particles has a kinetic energy of 3.8 Mev. Throug so that if one is fired head-o h what potential di fference would you have to accelerate these a particles in order that they would have enough energy on at a gold nucleus it cou uld reach a point 1.5 x 1014 m from the center of the nucleus? Each a particle in a beam of a particles has a kinetic energy of...
Each ? particle in a beam of ? particles has a kinetic energy of 5.0 MeV. Through what potential difference would you have to accelerate these a particles in order that they would have enough energy so that if one is fired head-on at a gold nucleus it could reach a point 1.0x10^-14 m from the center of the nucleus?