Question

Lester Hollar is vice president for human resources for a large manufacturing company. In recent years, he has noticed an increase in absenteeism that he thinks is related to the general health of the employees. Four years ago, in an attempt to improve the situation, he began a fitness program in which employees exercise during their lunch house To evaluate the program, he selected a random sample six months following the exercise program. Below are the results:

Employee Before    After

Bauman    6 5

Briggs 6    2

Dottelis 7 1

Lee 7 3

Perralt    4 3

Rielly    3 6

Steinmetz 5 3

Stoltz    6 7

At the 0.05 significance level, can he conclude that the number of absences has declined? Estimate the p-value.

a. State the decision rule for 0.05 significance level.

b. Compute the test statistic.

c.The p-value is

d. State your decision about the null hypothesis

Answer 1

Wallion loce collar is llice president for human resources for a large Rescured information is given by before, 66 ty cu o so efter 5 ♡ 1 B B 3 7 Chla. S we have to draw the tabular Lbefore Lor ld before her ܘ # 7 ܩ Jos twoa a to ko u cd-a) lk 75 0.5625 1.75 5.0625 175 18.0625 1.45 5.0625 1.75 0.5605 1.75 20.5625 1:15 0.0605 5 ܗ ܩ - 5605 ܩ Id = 14 I cd-aja =59.5 - deviation is we have to obtained the mean and standard Efere, Mean is

Standard deviation Valce is Tecd-a)² Sda v n 59.5 -18.5 C = 2.9154 Then 1.15 91 do 154 (sd - 2.0154 z we have to obtained the hot and alternatile hypothesis Efere, null bypothesis is (Ho: dp = 0 1 hod, Alternatille hypothesis is HA: llp so Colwate's given data is, @ State Decision raleis We have to obtained the decision ston Mule 14 asins sale by asing Flere, - It is a right taid test, then teritical -tex=0:05, dfent) Et(0.05, 87) etc0.05. +

t-Critical = 1.894157 A-critical = 1.Baub - Decision mulle w Beject to if t > tcrtical ieit » 1.8946 Lo not reject Ho, ift <tcritical ie, 1. Baub compute test tahtstic's we have to obtained the teet sing statistic of gillen dote in Elere test Gstartstic ics, hd-ho to salm G. 75-o] @.915416] 175 1.03074 -1.6atta t=1698) Chere fore, test Statistic iG 1.6981 © flable in he have to obtained the (fere, privalue by cosing gilbs Clata is P value = [ + tást, dfanu) = [ 1.698, df=84) [1.698, 7J

[p Wallwc. 0.06665 ) Therefore, Plaas is (0.066) (20.05 is O Sheil cpoor Chriksioni bomb have to Compare P-Kalos oro significarle, Doug Elere, placu za 0.066 005 ->We rejected lito al TAE0-05 that the reamber of absences signifiCarst Thos Concoudod that has declined.