Here negative velocity shows that velocity is in opposite direction to that of postion (displacement)
And so is acceleration.
If you still have any confusion anywhere then please let me know in the comments section.
2. +-12 points PSE6 2.P.015 A particle moves along the x axis according to the equation...
2. 2. 12 points PSE6 2.P.015. My Notes A particle moves along the x axis according to the equation x = 1.90 + 3.04t t2, where x is in meters and t is in seconds. (a) At t 2.90 s, find the position of the particle. (b) What is its velocity? (c) What is its acceleration? m/s 2 m/s
A particle moves along the x axis according to the equation x = 1.93 + 2.90t − 1.00t2, where x is in meters and t is in seconds. (a) Find the position of the particle at t = 3.10 s. m (b) Find its velocity at t = 3.10 s. m/s (c) Find its acceleration at t = 3.10 s. m/s2
A particle moves along the x axis according to the equation x = 2.06 + 2.95t - 1.0062, where x is in meters and t is in seconds. (a) Find the position of the particle at t = 2.80 s. m (b) Find its velocity at t = 2.80 s. m/s (c) Find its acceleration at t = 2.80 s. m/s2 Submit Answer
A particle moves along the x axis according to the equation x = 1.93 + 2.99t-1.00p, where x is in meters and t is in seconds. (a) Find the position of the particle at t2.60 s. (b) Find its velocity at t -2.60 s m/s (c) Find its acceleration at t-2.60 s m/s2
A particle moves along the x axis according to the equation x = 1.91 2.99t-1.00e, where x is in meters and t is in seconds. (a) Find the position of the particle at t 2.90 s (b) Find its velocity at t- 2.90 s m/s (c) Find its acceleration at t 2.90s m/s? My Note (a) Can the velocity of an object at an instant of time be greater in magnitude than the average velocity over a time interval containing...
A particle moves along the x axis according to the equation X(t) = 2 + 3t + 4t 2, where x is in meters and t is in seconds. What is the instantaneous acceleration at t = 3s A) 1.0 m/s? B) 3.0m/s? C) 4.0 m/s? D) 8.0 m/s? OOOO
Can I have this in details please Thank you! 21」A particle moves along the x axis according to the M equation x = 2.00 + 3.001-1.0012, where x is in meters and tis in seconds. At 3.00 s, find (a) the position of the particle, (b) its velocity, and (c) its acceleration.
A particle moves along the x axis. Its position is given by the equation x = 1.5 + 2.9t − 3.6t2 with x in meters and t in seconds. (a) Determine its position when it changes direction. m (b) Determine its velocity when it returns to the position it had at t = 0? (Indicate the direction of the velocity with the sign of your answer.) m/s
A particle moves along the x axis. Its position is given by the equation x = 2.1 + 2.7t − 3.5t2 with x in meters and t in seconds. (a) Determine its position when it changes direction. m (b) Determine its velocity when it returns to the position it had at t = 0? (Indicate the direction of the velocity with the sign of your answer.) m/s
A particle starts from rest at x = -1.8 m and moves along the x-axis with the velocity history shown. Plot the corresponding acceleration and the displacement histories for the 2.0 seconds. Find the time t when the particle crosses the origin. After you have the plots, answer the questions. Chapter 2, Practice Problem 2/015 A particle starts from rest at x = -1.8 m and moves along the x-axis with the velocity history shown. Plot the corresponding acceleration and...