Question

The spin-only magnetic moment (yso) can be calculated by the equation: piso-4 S(S +1), where S is the spin state. An equivalent equation is: jso= n(n+2), where n is the number of unpaired electrons. Note: 13 = 1.73 18 = 2.83 15 = 3.87 24 = 4.90 V35 = 5.92 1. What is the magnetic moment for (Fe(H:0).JSOA? 2. What is the magnetic moment for Cr(CO). ? 3. What is the magnetic moment for (NH4)2[CoBr.]? 100000! 4. What is the magnetic moment for [Rh(NH3).J(CIO4)3 ? 5. What is the magnetic moment for (Cr(en)](CIO);? 6. What is the magnetic moment for [Fe(bpy)3]SO.?

Answer 1

weak field ligand 1.Fe (H₂O) 504 & Fe (11) ; Outer E.C. = 3d 45° Hybridization a sp?d? H2O is a is complex is High spin or spin number free complex of Unpaired es (n=4 Mso = √4(4+2) = √24 = 4.90 2. Coccog ý crco) i outer E.c. = 3d us' Hybridization = d²sp3 I co is a strong field ligand 1. Complex is Low spin on spin paired n=0 i Mso = oil (NH4)₂ [co Bry] ; Cocii) ; outer til. = 3d7 Hybridization sped² Bš → weak field ligand is complex is High Spin number of Onpaned es (n)= 3 Mso = √3(3+2) = 515 = 3187 Rh (NH3)6] (6104) ; Rh (111) ; ontar E.C. = 426 Hybridization = d²sp3 in Low spin complex. no in uso o n a 5. (ercend] (C104)3 i Cr Cili) ; 3d² Hybridization - d²sp3 Since en is strong field ligand as the complex should be Low spin, but es remain in 3 trg Orbitals as Unpaired es cobeo. n=3 - Mlso = √3 (3+2) =/i5 = 3.87 6. [Fe (opy), Isoq ; Fe (11) ; 3d bpy' is a strong field ligand the Complex ů low spin or Spin paired. n=0 Mlso o