The no. of moles of He-gas = PV/RT = 442*3.5/62.364T = 24.806/T mol
The no. of moles of Ne-gas = 640*6.85/62.364T = 70.297/T mol
Mole fraction of He-gas = 24.806/(24.806+70.297) = 0.261
Mole fraction of Ne-gas = 1-0.261 = 0.739
Now, partial pressure He-gas = 442 torr * 0.261 = 115.3 torr
And the partial pressure of Ne-gas = 640 torr * 0.739 = 473.1 torr
Therefore, the final total pressure = 115.3 + 473 = 588.4 torr
The following problems are due next week but you should work on them with your group...
(W) 36.0 cm (ii) - 59,0 cm The following problems are due next week but you should work on them with your group today 4.(20pts) Valves closed He ideal gas) (Flask on left) Neideal gas) (Flask in middle) Paskon Right V-3.50 L V = 6.85 L V=3.00 L P = 442 torr P=640 torr P=0 (vacuum) When the valves are open, the gases will mix. Assuming that the temperature is constant, what is the final total pressure in torr? Hint:...
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