Solution:-
Given that
Using standard normal table,
P( -z < Z < z) = 0.80
= P(Z < z) - P(Z <-z ) = 0.0.80
= 2P(Z < z) - 1 = 0.0.80
= 2P(Z < z) = 1 + 0. 0.80
= P(Z < z) = 1.80 / 2
= P(Z < z) = 0.90
= P(Z < 1.28 ) = 0.90
= z ± 1.28
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