Question

A compound with molecular formula C H140, displays the following IR, 1 H NMR and SC NMR spectra. Propose a structure for this
ppm 180 160 140 120 10080604620 PPM
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calculation of Double bond equalent (DBE) for GH1409: - X THE cn H2n+2 bor ca saturated Hydrogens = 16H long to t ₂ H16 boricbased on H NMR Data the probable structure is с — си— сия - -о- сномз 4 сосій в - Isopropyl butanoate de Chile 5 3 types of tdla NHR Data de 6 Sigma 18 (6 bitterent types recentes CHO-CHIC-o Te Chat G H3C-CH₂-CHI laj (bj (C ( d les Ichy by G tute Ca

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