5)
Molar mass of C2H2,
MM = 2*MM(C) + 2*MM(H)
= 2*12.01 + 2*1.008
= 26.036 g/mol
mass(C2H2)= 5.25 g
use:
number of mol of C2H2,
n = mass of C2H2/molar mass of C2H2
=(5.25 g)/(26.04 g/mol)
= 0.2016 mol
Since Δ H is negative, heat is released
when 2 mol of C2H2 reacts, heat released = 2602.0 KJ
So,
for 0.2016 mol of C2H2, heat released = 0.2016*2602.0/2 KJ
= 262 KJ
Answer: b
Only 1 question at a time please
5. How much heat is produced by the combustion of 5.25 g of acetylene (C2H2, 26.036...
1. A system does 425 kJ of work and loses 125 kJ of heat to the surroundings. What is the change in internal enery of the system? a) 550 kJ c) -300 kJ e) OkJ b) 300 kJ d) - 550 kJ 2. How many grams of NaBr (102.89 g/mol) are contained in 250.0 mL of a 0.200 M solution of sodium bromide a) 50.0 g c) 5.14 g c) 0.0500 g b) 20.6 g d) 0.486 g 3. A...
all 3. Calculate the heat released (kJ) in the reaction of 1.35L of acetylene (C2H2) and 0.235L of hydrogen gas at STP to form ethane gas as determined by the following equation: C2H2(g) + 2H2() → C2H6(g) Given: 2C2H2(g) +502(g) + 4CO2(g) + 2H20(g) 2C2H.(g) + 702(g) → 4CO2(g) + 6H20(g) 2H2(g) + O2(g) → 2H2O(g) AH = -2320 kJ/mol AH = -3040 kJ/mol AH = -572 kJ/mol
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