Homework Answers
Given:
P = 1.06 atm
V = 58.3 L
T = 22.1 oC
= (22.1+273) K
= 295.1 K
find number of moles using:
P * V = n*R*T
1.06 atm * 58.3 L = n * 0.08206 atm.L/mol.K * 295.1 K
n = 2.552 mol
From reaction,
Mol of NaN3 reacted = (2/3)*mol of N2 formed
= (2/3)*2.552 mol
= 1.70 mol
Answer: 1.70 mol
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