• H = 3.25t^3
dH/dt = 9.75t^2
at time t = 1.80s, H = 18.954m.
The velocity of the mailbag is u = 31.59m/s. (upward)
Acceleration due to gravity = - 9.8m/s^2
Displacement h = - 18.954 m. (minus since it is below the
origin)
From v^2 -u^2 = 2as
v^2 = 2*(-9.8) *(-18.954) +31.59^2
v = - 37.00 m/s taking the minus value since the velocity we want
is down ward.
• Distance = average velocity * time
-18.954 = [31.59 + (-37.00)] *t /2
t =7.00 s
===============================
My Notes Notes Ask Your Te O Ask Your Toachar 1 points | Previcun Anewers SerPSETO...
2. +0/3 points | Previous Answers 4/7 Submissions Used My Notes The height of a helicopter above the ground is given by h 2.95t3, where h is in meters and t is in seconds. Att2.05 s the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground? [HINT: Make a list of important clock readings. Make a motion map for the bag before and after it is dropped. Make a list of known quantities....
3.25t, where h is in meters and t is in seconds. At t The height of a helicopter above the ground is given by h after its release does the mailbag reach the ground? 1.65 s, the helicopter releases a small mailbag. How long
44. The height of a helicopter above the ground is givenby, where h is in meters and t is inseconds. After 2.00s, the helicopter releases a small mailbag. Howlong after its release does the mailbag reach the ground? Show allwork!
The height of a helicopter above the ground is given by h = 2.80t3, where h is in meters and t is in seconds. At t = 1.90 s, the helicopter releases a small mailbag. (a) How long after its release does the mailbag reach the ground? (b) With what velocity does the mailbag hit the ground?
The height of a helicopter above the ground is given by h = 3.25, where h is in meters and t is in seconds. At t after its release does the mailbag reach the ground? 1.73 1.65 s, the helicopter releases a small mailbag. How long x s
The height of a helicopter above the ground is given by h 3.150, where his in meters and is in seconds. Att - 1.65 s, the helicopter releases a small mailbag: How long after its release does the mailbag reach the ground? Need Help? Read
The height of a helicopter above the ground is given by h = 2.90t3, where h is in meters and t is in seconds. At t = 1.80 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground? Please show how to solve this step by step and explain clearly and neatly
The height of a helicopter above the ground is given by h = 3.15t3, where h is in meters and t is in seconds. At t = 2.45 s, the helicopter releases a small mailbag.How long after its release does the mailbag reach the ground?THE ANSWER ISNT 3.07315806
The height of a helicopter above the ground is given by h = 2, 75t3, where h is in meters and t is in seconds. At t = 2.10 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground? [HINT: Make a list of important clock readings. Make a motion map for the bag before and after it is dropped. Make a list of known quantities. How fast is the bag going...
The height of a helicopter above the ground is given by h-2-95t3, where h is in meters and t is in seconds. At t = 1.65 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground? [HINT: Make a list of important clock readings. Make a motion map for the bag before and after it is dropped. Make a list of known quantities. How fast is the bag going before it is...