Question

1c Two thin, insulating sheets, one with uniform charge density-σ and the other + σ are separated by a distance s. 1-0 Find E between the sheets and to either side of the sheet (at distances from sheet that are small compared to the dimensions of the sheet). | | +σ

Answer 1

If the magnitude of surface charge density is same then the magnitude of electric field also same for thin insulating sheet and it is independent of distance.

As we know that, Electric field due to thin insulating sheet, having charge density sigma is, Vertical-bar E^rightarrow Vertical-bar = Vertical-bar sigma/2 E_0 Vertical-bar [magnitude] Direction of electric field will away from sheet, if the charge density is positive and toward sheet if it is negative. So, for any point A, between sheets E_net = E_(+) + E_(minus) = Vertical-bar 6/2 E_0 Vertical-bar + Vertical-bar minus 6/2 E_0 Vertical-bar = 6/E_0 for B and C, it will be zero i.e E_net = 0 Because, magnitude is same but direction is opposite.