Part A)
We know tha
E = kq/r^2 for both charges
Since they are both negative, they will provide opposite direction E field at point P, so we will subtract one from another
From Q2,
E = (9 X 10^9)(1.4 X 10^-6)/(1.8)^2
E = 3888.89 N/C to the left
From Q1,
E = (9 X 10^9)(1.8 X 10^-6)/(1.3)^2
E = 9585.8 N/C to the right
The net E field = 9585.8 - 3888.89 = 5696.91NC
Part B)
Apply F = qE
F = (1.8 X 10^-6)(5696.91)
F = 0.01025 N
Course Sontents HOMEWORK Set 1 ( due Thurs.... Electric field and force due to. Timer Notes...
ゆCourse Contents , HOMEWORK » Set 1 (due Thurs Orer□NotesjEvaluateeFeedbackシ The figure shows two point charges. Calculate the magnitude of the electric field at point P. Use the following Electric field and force data: Q1-1.60 C, Q1.20 C, d1- 1.40 m, d2 1.60 m. 02 P 0 Tries 7/20 Previous Tries Calculate the size of the force on a charge Q+1.20 uC placed at P due to the two charges from the previous problem Sms Araer Tries 0/20 @Post Discussion...
Course Contents Homework Set 2 ( due Friday Electric field and force due to . 4 Timer NotesEvaluate FeedbackPrint The tigure shows two point charges, Calculate the magnitude of the electric field at point P. Use the following data: Q1 - 1.90 HC, Q2 1.10 HC, d1 1.50 m, d2- 1.70 m. 02 Submit Answer Tries 0/12 Calculate the size of the force on a charge Q+1.20 HC placed at P due to the two charges from the previous problem....
The figure shows two point charges. Calculate the magnitude of the electric field at point P. Use the following data: Q1=-1.60 μC, Q2=- 1.30 pC, d1= 1.10 m, d2= 1.80 m. 2 Submit Answer Tries 0/99 Calculate the size of the force on a charge Q = +1.20 μC placed at P due to the two charges from the previous problem Submit Answer Tries 0/99
The figure shows two point charges. Calculate the magnitude of the electric field at point P. Use the following data: Q1= + 1.60 pC, Q2= +1.40 HC, d1- 1.50 m, d2- 1.60 m Q, P 2 2 Submit Answer Tries 0/12 Calculate the size of the force on a charge Q =-1.30 μC placed at P due to the two charges from the previous problem. Submit Answer Tries 0/12
2 The figure below shows two charges. Calculate the magnitude of the electric field at point P. d2 Q1=-1.70 pC Q2=-1.30 μC d1= 1.50 m d2= 1.70 m Submit Answer Tries 0/10 Calculate the size of the force on a charge Q= +1.20 μC placed at P due to the two charges from the previous problem. Submit Answer Tries 0/10
The figure shows two point charges. Calculate the magnitude of the electric field at point P. Use the following data : Q1-+ 1.80 pC, Q2-+ 1.40 μC, di-1.30 m, d2= 1.70 m. Q, P22 2 1.3945 104-4 N CA-1 Submit Answer Incorrect. Tries 3/99 Previous Tries Calculate the size of the force on a charge Q-1.10 HC placed at P due to the two charges from the previous problem.
The figure shows two point charges. Calculate the magnitude of the electric field at point P. Use the following data: Q1-+ 1.90 μC, Q2= + 1.50 μC, di- 1.40 m, d2- 1.80 m. Q, P0 "X Submit Answer Tries 0/12 Calculate the size of the force on a charge Q =-1.20 pC placed at P due to the two charges from the previous problem.
The figure shows two point
charges. Calculate the magnitude of the electric field at point P.
Use the following data: Q1= - 1.80 μC, Q2= -
1.10 μC, d1= 1.40 m, d2= 1.60 m.
Incorrect.
Tries 1/99
Previous Tries
Calculate the size of the force on a charge Q = +1.10 μC placed
at P due to the two charges from the previous problem.
2 2 We were unable to transcribe this image
The figure shows two point charges. Calculate the magnitude of the electric field at point P. Use the following data: Q1= + 1.80 μC, Q2= + 1.20 μC, di: 1.40 m, d2-1.80 m Q, P 22 2 Submit Answer Tries 0/99 Calculate the size of the force on a charge Q-_1.20 μC placed at P due to the two charges from the previous problem
1) The figure shows two point charges. Calculate the magnitude of the electric field at point P. Use the following data: Q1= + 1.80 μC, Q2= + 1.30 μC, d1= 1.20 m, d2= 1.70 m.2) Calculate the size of the force on a charge Q = -1.70 μC placed at P due to the two charges from the previous problem.