Question

3 The value of Kp for the reaction of nitrogen and oxygen to make nitrogen monoxide is 0.000376. The initial partial pressure of nitrogen monoxide is 1.164 atm with no nitrogen or oxygen. What is the equilibrium partial pressure (in atm) of oxygen?

Answer 1

Na t O - 200 K = 0.000376. o o 1.167 atm (Initials x x 1.164-2X (equilibrium) aut cx' be the decrease in the concentration of No to reach the equilibrium ko = [NO]" (1.164-22) 2 (N] (0) X2 0-000376 = (1.164-22) 2 0.000376 XX² = (1-16 4- 202 0.000326x² = 1.164-2X 0-06131883 887 X= 1.164-2X (2+0.06731383887)X = 1.164 x= 0.564687 {N ,J = ( x ) = x= 0.564687 M. [N) = 1.164-2(0.5668 77= 0.034626 m.