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Use the References to access important values if needed Calculate the percentage composition for NO2. Mass percentage of nitrogen = Mass percentage of oxygen = Submit Answer Retry Entire Group 8 more group attempts remaining

Answer 1

1 NO2 & Mw = 14 +32 = 46 g/mol mass of N = 14 mass of 0 = 16+16=32 So. % mass of N= mass of N x 100% total mass - X100% = 30.43% 46 So, to mass of d = 32 x 100 = 69.57% 2) mass of iron = 53.959 mass of iron oxide = 77.149 so, mass of oxygen = 77149-53.959 - 23.19 g so, empirical formula can be calculated by taking mole ratio of fe ando -fe : 0 53.959 22.193 55.85 g/mol T6 g 1 mol = 0.966 : 1,45 2 : 3 so, empirical formula = fe2O3 3) mass of copper = g. 9659 mass of copper bromide = 22.499 so, mass of bromine = 22.49 g- 9.9619 22.699-9.9659 = 12.5259

mole rates of a empirical formula can be calculated by taking Cu and Br. So, mole ratio of Cu an Bo - 9.9659 12.5259 63.559 m 79.9 g/mol = 0.157 : 0.157 so, empirical formula Cu Br masl. Of 'S' 15.71% mass 7 of 0.44.557. many o ci 19.74% let total mas of compound be 100g So, mass of 's' = 35.71g mass of 'o' = 46.559 mars of cla 19.769 empirical formula can be calculated by talking mole ratio of 's', 6 and 'cd so, mole of's mole of o : mole of ci 35.719 46.559 19.749 - 32 g/mol 16 g/mol. 35.45g/mol 1116 : 2.78 : 0.557 = 2 : 5 :1 So, empirical for mula - Szofa em birical was = 179.69 and molar may = 179.6 mol as molar mass = empirical mass so molecular formula = S₂ Of Cl.

Y mass of 'C'a 52.13x .), mas of 'H' = 13.15% % mau of 0 : 34.72%. let mass of compound be 100 g so, mass of 'C' = 52.13 g maus of H: 13.15 g mars of o' = 34.729 empirical formula can be calculate by taking mole ratio of 'c' t' and a so, mole of 'c: mole of H' : mol of 'o' - 52.139 13.159 3 4.729 72 g/mol. glmal 16 g/mol : 4.344 : 13-15 :2.17 so, empirical formula = C2 Hoo empirical mass = 46.099 and molecular mau 46.099 an empiricel may = molecular mais so molecular formula - empirical formula - C2H60 6) t.mass of c= 3.6227 4. mass of 'Br = 96.38% bet man of compound be 100 g so, mass of 'c'= 3.6229 mass of 'Br = 96.389 empirical for mula can be calculated by taking mole ratio of Ć' and 'Br so, mole of 'c : mole of Br = 3.6229 96:3! 79.99/mil 12 g/mol : 0.3 : 12

So, empirical formula = CBr 4 empirical mass = 331069 and molecular forass = 331.68/mol as molecular mass = empirical mass so molecular formula = empirical formula = C Bry