What is the oxidation state of nitrogen the following redox reaction?
Cu(s) + HNO3(aq) → Cu2+(aq) + NO(g)
For HNO3:
Oxidation number of O = -2
Oxidation number of H = +1
lets the oxidation number of N be x
use:
1* oxidation number (H) + 3* oxidation number (O) + 1* oxidation
number (N) = net charge
1*(+1)+3*(-2)+1* x = 0
-5 + 1 * x = 0
x = 5
So oxidation number of N = +5
Oxidation number of each element in HNO3 is
O=-2
H=+1
N=+5
For NO:
Oxidation number of O = -2
lets the oxidation number of N be x
use:
1* oxidation number (O) + 1* oxidation number (N) = net
charge
1*(-2)+1* x = 0
-2 + 1 * x = 0
x = 2
So oxidation number of N = +2
Oxidation number of each element in NO is
O=-2
N=+2
N in HNO3 has oxidation state of +5
N in NO has oxidation state of +2
So, N in HNO3 is reduced to NO
Oxidation state of N changes from +5 to +2
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