Question

1. Two electrons in a vacuum exert force of F=2.55*10^-8 on each other. They are then moved so that they are separated by x=8.9 times their original distance

Part a.) what is the force , in Newton’s , that the electrons experience at the new separation distance ? Numeric value is expected and not an expression ,Fn= ?

Part b.) how far apart , in meters , were the electrons originally? Numeric : a numeric value is expected and not an expression d= ?

Answer 1

From coulombs law

Force due to two point charges at distance r is

F =k*q1*q2/(r^2)

From this ,we conclude that the Force is inversely proportional to the square of the distance between two point charges .