Question

171-c CHAPTER 6 Chemical Calculations: Formura 6- 6-37 Determine the number of grams of sulfur present in each of the following quantities. a. 3.01 X 1023 S,O molecules b. 3 SAN4 molecules c. 2.00 moles SO, molecules

Answer 1

Ans 6.37 :

a)

Number of mol of S2O = number of molecules / (6.022 x 10²³)

= (3.01 x 10²³) / (6.022 x 10²³)

= 0.5 mol

each mol S2O weighing 80.13 g has 64.12 g of sulfur

so mass of sulfur here :

= 0.5 mol x 64.12 g/mol

= 32.06 g

b)

S4N4 molar mass= 184.3 g / mol

each mol has 6.022 x 10²³ molecules

so here number of mol = 3 molecules / (6.022 x 10²³ molecule / mol)

= 5.0 x 10^-24 mol

each mol compound weighing 184.3 g has 128.3 g sulfur

so 5.0 x 10^-24 mol compound will have :

= 5.0 x 10^-24 mol x 128.3 g/mol

= 6.41 x 10^-22 g

c)

Each mol SO2 has 32.065 g of sulfur

so 2.00 mol of SO2 will have :

= 2.00 mol x 32.065 g/mol

= 64.12 g of sulfur