Homework Answers
AgNO3 and KOH react to form AgOH which has Ksp = 1.52 x 10^ -8
Ksp = [Ag+] [OH-]
1.52 x 10^ -8 = [Ag+] ( 0.0179)
[Ag+] = 8.49 x 10^ -7 M
Ag+ moles = M x V ( inL) = 8.49 x 10^ -7 mol/L x 0.075L = 6.37 x 10^ -8 mol
Ag+ mass = moles x atomic mass of Ag = 6.37 x 10^ -8 mol x 107.87 g/mol
= 6.87 x 10^ -6 grams
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