Question

The total degrees of freedom of the CIF3 molecule (T-shaped, Cav point group) are 4Ai + 3. A2+3B1+4B2. Deduce the number of absorption lines observed in the IR and Raman spectra of CIF3 (4p). Identify the number and symmetry labels of the corresponding normal vibrational modes, using the table below to report the results. (6p). IR Raman 3 #absorptions # normal vibrational modes symmetry labels of vibrational modes

Answer 1

- Le Fj (. Chlorine trifluoride) has a trigonabify ramsidal shape and have two equatorial love paid making the final structure T- shaped It has Cap point group and total degree of freedom are 4A, + A 2 + 3B, + 4Ba. IR active #absorptrom = 3 de 3 A + B + 232 Raman active #aboorlition = 3 in 3A + B + 2B 2. # Normal vibrational moder geach for If and Raman = 3 Ay+B, +20 Rotational = A et B, toe Tramlation af = A + B + Be Symmetry label of vibrationa by labelk of vibrational moder ( 344-6=6; ie 34-6) For It a Bi For Ramana Aa